An array is a container object that holds a fixed number of values of a single type. To create an array in C, we can do
points to the base address of the array.
In this challenge, you have to create an array of size
.
The next line contains
int arr[n];
. Here, arr, is a variable array which holds up to
integers. The above array is a static array that has memory allocated
at compile time. A dynamic array can be created in C, using the malloc
function and the memory is allocated on the heap at runtime. To create
an integer array, of size , int *arr = (int*)malloc(n * sizeof(int))
, where points to the base address of the array.
In this challenge, you have to create an array of size
dynamically, input the elements of the array, sum them and print the sum of the elements in a new line.
Input Format
The first line contains an integer,
The next line contains
space-separated integers.
Constraints
Output Format
Print in a single line the sum of the integers in the array.
Sample Input 0
6
16 13 7 2 1 12
Sample Output 0
51
Sample Input 1
7
1 13 15 20 12 13 2
Sample Output 1
76
Solution in C:-
#include <stdio.h>
int main()
{
int n,val,sum=0;
scanf("%d",&n);
while(n--)
{
scanf("%d",&val);
sum+=val;
}
printf("%i",sum);
}
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Thanks..