For Loop in C

Objective
In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be repeatedly executed.
The syntax for this is

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>

• expression_1 is used for intializing variables which are generally used for controlling the terminating flag for the loop.
• expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
• expression_3 is generally used to update the flags/variables.

A sample loop will be

for(int i = 0; i < 10; i++) {
    ...
}

Task
For each integer
in the interval (given as input) :

• If

, then print the English representation of it in lowercase. That is "one" for , "two" for

, and so on.

Else if

and it is an even number, then print "even".

Else if

• and it is an odd number, then print "odd".

Input Format

The first line contains an integer,

.
The seond line contains an integer,

.

Constraints

Output Format

Print the appropriate english representation,even, or odd, based on the conditions described in the 'task' section.
Note:

Sample Input

8
11

Sample Output

eight
nine
even
odd

Solution in C:-

#include <stdio.h>

#include <string.h>

#include <math.h>

#include <stdlib.h>

int main() 

{

    int a, b;

    scanf("%d\n%d", &a, &b);

    

    char labels[11][6] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "even", "odd"};

    int labels_index;

      for (int i=a; i<=b; i++) {

        labels_index = i <= 9 ? i - 1 : 9 + i % 2;

        printf("%s\n", labels[labels_index]);

    }

    return 0;

}